(9x^2-12x+4)(x+3)=0

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Solution for (9x^2-12x+4)(x+3)=0 equation: 


Simplifying
(9x2 + -12x + 4)(x + 3) = 0

Reorder the terms:
(4 + -12x + 9x2)(x + 3) = 0

Reorder the terms:
(4 + -12x + 9x2)(3 + x) = 0

Multiply (4 + -12x + 9x2) * (3 + x)
(4(3 + x) + -12x * (3 + x) + 9x2 * (3 + x)) = 0
((3 * 4 + x * 4) + -12x * (3 + x) + 9x2 * (3 + x)) = 0
((12 + 4x) + -12x * (3 + x) + 9x2 * (3 + x)) = 0
(12 + 4x + (3 * -12x + x * -12x) + 9x2 * (3 + x)) = 0
(12 + 4x + (-36x + -12x2) + 9x2 * (3 + x)) = 0
(12 + 4x + -36x + -12x2 + (3 * 9x2 + x * 9x2)) = 0
(12 + 4x + -36x + -12x2 + (27x2 + 9x3)) = 0

Combine like terms: 4x + -36x = -32x
(12 + -32x + -12x2 + 27x2 + 9x3) = 0

Combine like terms: -12x2 + 27x2 = 15x2
(12 + -32x + 15x2 + 9x3) = 0

Solving
12 + -32x + 15x2 + 9x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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